Higher Maths · Applications

The Circle | Higher Maths

The Circle is one of the most reliable mark-grabbers in Higher Maths. Tangents to circles and intersections with straight lines are tested almost every year. Confidence with completing the square is essential.

SQA Higher MathsSpecification: ApplicationsUnit 2 (legacy)

Circle equations

Circle centre (a, b) radius r: (x − a)2 + (y − b)2 = r2
General form: x2 + y2 + 2gx + 2fy + c = 0
Centre: (−g, −f)
Radius: r = √(g2 + f2 − c)
A real circle exists only when g2 + f2 − c > 0.

Worked example

Worked example — Tangent to a circle

Problem: Find the equation of the tangent to the circle (x − 2)2 + (y + 1)2 = 25 at the point P(5, 3).

  1. Identify the centre.
    Centre C = (2, −1).
  2. Find the gradient of the radius CP.
    mCP = (3 − (−1)) / (5 − 2) = 4/3
  3. Tangent gradient is the negative reciprocal.
    mtangent = −3/4
  4. Equation of tangent through (5, 3).
    y − 3 = (−3/4)(x − 5) ⇒ 4y + 3x = 27

Practice questions

Try these SQA-style questions. Tap "Show answer" to check your working.

Practice questions

  1. Find the centre and radius of x2 + y2 − 6x + 4y − 12 = 0.
    Show answer
    Centre (3, −2), radius 5
  2. Does the line y = x + 1 cut the circle x2 + y2 = 25? If so, find the points.
    Show answer
    Substitute: x2 + (x+1)2 = 25 ⇒ 2x2 + 2x − 24 = 0 ⇒ x = 3 or −4. Points: (3, 4) and (−4, −3)
  3. Find the equation of the circle with centre (−1, 4) and radius √10.
    Show answer
    (x + 1)2 + (y − 4)2 = 10
  4. Show that the line y = 2x + 5 is a tangent to x2 + y2 = 5.
    Show answer
    Substituting gives 5x2 + 20x + 20 = 0 ⇒ x2 + 4x + 4 = 0 ⇒ (x + 2)2 = 0. Repeated root means tangent.
  5. Find the value(s) of k such that the line y = x + k is a tangent to x2 + y2 = 8.
    Show answer
    2x2 + 2kx + k2 − 8 = 0. Discriminant 4k2 − 8(k2 − 8) = 0 ⇒ k2 = 16. k = ±4

Common mistakes

Common mistakes & how to avoid them

  • Mistaking the centre as (g, f) instead of (−g, −f) in the general form.
  • Forgetting to check that the radius is real (g2 + f2 − c > 0) before claiming a circle exists.
  • Using the gradient of the radius for the tangent — they are perpendicular.

Frequently asked questions

Is the circle equation on the SQA formula sheet?
Yes — both forms (centre-radius and general) are on the Higher formula sheet. But you must still know how to extract the centre and radius from the general form.
How do I prove a line is a tangent without using the gradient method?
Substitute the line into the circle. Solve the resulting quadratic. If the discriminant is zero, there is exactly one intersection — meaning the line is a tangent.
Can a circle pass through a given set of points?
Three non-collinear points uniquely define a circle. You can find its equation by setting up three equations in g, f and c and solving simultaneously.

Related Higher Maths topics

These topics often appear together in SQA exam questions.

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